1156A - Inscribed Figures - CodeForces Solution


geometry *1400

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Python Code:

import sys
import math

CIRCLE = 1
TRIANGLE = 2
SQUARE = 3

n = int(sys.stdin.readline().strip())
arr = sys.stdin.readline().split()
arr = [int(e) for e in arr]
total = 0
isInfinite = False

for i in range(1,n):
    if arr[i] == SQUARE and arr[i-1] == TRIANGLE:
        isInfinite = True
        break
    if arr[i] == SQUARE and arr[i-1] == CIRCLE:
        total += 4
    if arr[i] == CIRCLE and arr[i-1] == TRIANGLE:
        total += 3
    if arr[i] == CIRCLE and arr[i-1] == SQUARE:
        total += 4
    if arr[i] == TRIANGLE and arr[i-1] == SQUARE:
        isInfinite = True
        break
    if arr[i] == TRIANGLE and arr[i-1] == CIRCLE:
        if i > 1 and arr[i-2] == SQUARE:
            total += 2
        else:
            total += 3


if isInfinite:
    print("Infinite")
else:
    print("Finite")
    print(total)

C++ Code:

#include <bits/stdc++.h>
using namespace std;
#define int long long

int32_t main(){
	ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	int n;
	cin>>n;
	vector<int> a(n);
	bool flag=0;
	int ans=0;
	for(int i=0;i<n;i++){
		cin>>a[i];
		if(i>0){
			if(min(a[i-1],a[i])==2 && max(a[i],a[i-1])==3){
				flag=1;
			}
			else if(min(a[i-1],a[i])==1 && max(a[i],a[i-1])==2){
				ans+=3;
			}
			else if(min(a[i-1],a[i])==1 && max(a[i],a[i-1])==3){
				ans+=4;
			}
		}
		if(i>1){
			if(a[i-2]==3 && a[i-1]==1 && a[i]==2){
				ans--;
			}
		}
	}
	if(flag)cout<<"Infinite\n";
	else{
		cout<<"Finite\n";
		cout<<ans<<endl;
	}
	
	return 0;
    }
 


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